2x^2-8x+32=5

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Solution for 2x^2-8x+32=5 equation:


Simplifying
2x2 + -8x + 32 = 5

Reorder the terms:
32 + -8x + 2x2 = 5

Solving
32 + -8x + 2x2 = 5

Solving for variable 'x'.

Reorder the terms:
32 + -5 + -8x + 2x2 = 5 + -5

Combine like terms: 32 + -5 = 27
27 + -8x + 2x2 = 5 + -5

Combine like terms: 5 + -5 = 0
27 + -8x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
13.5 + -4x + x2 = 0

Move the constant term to the right:

Add '-13.5' to each side of the equation.
13.5 + -4x + -13.5 + x2 = 0 + -13.5

Reorder the terms:
13.5 + -13.5 + -4x + x2 = 0 + -13.5

Combine like terms: 13.5 + -13.5 = 0.0
0.0 + -4x + x2 = 0 + -13.5
-4x + x2 = 0 + -13.5

Combine like terms: 0 + -13.5 = -13.5
-4x + x2 = -13.5

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -13.5 + 4

Reorder the terms:
4 + -4x + x2 = -13.5 + 4

Combine like terms: -13.5 + 4 = -9.5
4 + -4x + x2 = -9.5

Factor a perfect square on the left side:
(x + -2)(x + -2) = -9.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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